Difference between revisions of "RyansTests"

Revision as of 22:44, 30 August 2017

$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$

$$x=1a \over 2b$$

<math>{ T }_{ ij }=\sum _{ ij }^{ }{ { e }^{ ij } } \left\lceil \ln { { X }_{ ij } } \right\rceil <math>

Revision as of 22:43, 30 August 2017 (view source) JulieDunbar (Talk \| contribs) (Undo revision 8333 by JulieDunbar (talk)) ← Older edit		Revision as of 22:44, 30 August 2017 (view source) JulieDunbar (Talk \| contribs) (Undo revision 8334 by JulieDunbar (talk)) Newer edit →
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	$$x=1a \over 2b$$		$$x=1a \over 2b$$

−	$${ T }_{ ij }=\sum _{ ij }^{ }{ { e }^{ ij } } \left\lceil \ln { { X }_{ ij } } \right\rceil$$	+	:<math>{ T }_{ ij }=\sum _{ ij }^{ }{ { e }^{ ij } } \left\lceil \ln { { X }_{ ij } } \right\rceil <math>