# Difference between revisions of "RyansTests"

JulieDunbar (Talk | contribs) |
JulieDunbar (Talk | contribs) (Undo revision 8327 by JulieDunbar (talk)) |
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$$x=1a \over 2b$$ | $$x=1a \over 2b$$ | ||

− | + | :<math>{ T }_{ ij }=\sum _{ ij }^{ }{ { e }^{ ij } } \left\lceil \ln { { X }_{ ij } } \right\rceil <math> |

## Revision as of 22:42, 30 August 2017

$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$

$$x=1a \over 2b$$

- <math>{ T }_{ ij }=\sum _{ ij }^{ }{ { e }^{ ij } } \left\lceil \ln { { X }_{ ij } } \right\rceil <math>